| Author | Message | ||
     Lau Kai Kwong Username: lkk Registered: 04-2003 |
A non-uniform rod of weight 40N and length 1m is suspended by a single string attached to the mid-point of the rod. If the rod is horizontal when a weight of 30N is attached to one end of the rod, find the supporting force which would be required at the opposite end to keep the rod horizontal when the 30N weight is removed. ¾G·qùÚ, please post your solution. | ||
| 971165 Username: 971165 Registered: 04-2003 |
let X be the distance between the mid-pt of rod and c.g. Let 2L be the length of the rod Let F be the supporting force when the weight is not removed, take moment about mid-point, 30L=40X when the weight is removed, take moment about mid-point again, FL =40X therefore F=30N | ||
| Lau Kai Kwong Username: lkk Registered: 04-2003 |
Okay. Fine. But, please use small letters for distances. |